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Json 解析的一个范例
阅读量:286 次
发布时间:2019-03-01

本文共 2624 字,大约阅读时间需要 8 分钟。

JSON????????????????????????????????????????Java??JSON???????????????????

1. ??JSON???????

?Java????JSON????????? JSONObject ? JSONArray?JSONObject ????????????????? JSONArray ???????????????????????????JSON???

2. ???????

?????????????????????????????????????

public static List
parseProgrammersJson(String json) { List
programmersList = new ArrayList<>(); try { JSONObject jsonObject = new JSONObject(json); JSONArray programmersArray = jsonObject.getJSONArray("programmers"); for (int i = 0; i < programmersArray.length(); i++) { String firstName = programmersArray.getJSONObject(i).getString("firstName"); String lastName = programmersArray.getJSONObject(i).getString("lastName"); String email = programmersArray.getJSONObject(i).getString("email"); programmersList.add(firstName + lastName + email); } } catch (JSONException e) { e.printStackTrace(); } return programmersList;}

3. ??????

??????????????????????????????????

public static List
parseAuthorsJson(String json) { List
authorsList = new ArrayList<>(); try { JSONObject jsonObject = new JSONObject(json); JSONArray authorsArray = jsonObject.getJSONArray("authors"); for (int i = 0; i < authorsArray.length(); i++) { String firstName = authorsArray.getJSONObject(i).getString("firstName"); String lastName = authorsArray.getJSONObject(i).getString("lastName"); String genre = authorsArray.getJSONObject(i).getString("genre"); authorsList.add(firstName + lastName + genre); } } catch (JSONException e) { e.printStackTrace(); } return authorsList;}

4. ???????

??????????????????????????????????????

public static List
parseMusiciansJson(String json) { List
musiciansList = new ArrayList<>(); try { JSONObject jsonObject = new JSONObject(json); JSONArray musiciansArray = jsonObject.getJSONArray("musicians"); for (int i = 0; i < musiciansArray.length(); i++) { String firstName = musiciansArray.getJSONObject(i).getString("firstName"); String lastName = musiciansArray.getJSONObject(i).getString("lastName"); String instrument = musiciansArray.getJSONObject(i).getString("instrument"); musiciansList.add(firstName + lastName + instrument); } } catch (JSONException e) { e.printStackTrace(); } return musiciansList;}

5. ??

??????????????????JSON????????????????????????????????????????????????????JSON???????

转载地址:http://jszo.baihongyu.com/

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